Timothy Wittig

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Multidimensional arrays in C#

Published Aug 29, 2019

Quick question for you: what’s the difference between this syntax

static void UseMultidimensionalArray(int[][] multidimensionalArray)
{
    Console.WriteLine(multidimensionalArray[0][0]);
}

and this syntax?

static void UseMultidimensionalArray(int[,] multidimensionalArray)
{
    Console.WriteLine(multidimensionalArray[0,0]);
}

I was recently working on a problem that involved a two-dimensional array and found myself stumbling over this small syntax difference.

Now, I probably haven’t had to deal with multidimensional arrays since computer science classes in college. It turns out that’s why I was getting tripped up. Back then, I was working in C++ and Java and if you wanted a 2x2 matrix, you declared or initialized it with those dimensions:

// C++
int twoByTwo[2][2] = { {1,2}, {3,4} };
// Java
int[][] twoByTwo = new int[2][2];

But in C#, if you ever find yourself writing [2][2] to declare or initialize an array, you’re doing something wrong. This is a compilation error:

var twoByTwo = new int[2][2];

But these aren’t:

var twoByTwo_v1 = new int[2][];
var twoByTwo_v2 = new int[2,2];

The first version is a jagged array, meaning that each array entry is an array of potentially different length e.g.

int[][] jaggedArray = new int[2][] {
    new int[1] {44},
    new int[3] {1,2,3}
};
Console.WriteLine(jaggedArray[1][1]); // 2

The second version is what we want if we’re looking for rigid dimensions e.g.

int[,] twoByTwo = new int[2,2] {
    {1,2},
    {3,4}
};
Console.WriteLine(twoByTwo[0,1]); // 2

It boils down to the following in C#:

  • Array dimensions are never specified in the declaration
  • Array dimensions are required in the initialization
  • [][] == jagged array
  • [,] == multidimensional array